AcWing
796. 子矩阵的和
二维的前缀和。
计算前缀和数组:s[i][j] = a[i][j] + s[i-1][j] + s[i][j-1] - s[i-1][j-1]
;
计算二维区间和:s[x1~x2][y1~y2] = s[x2][y2] - s[x1-1][y2] - s[x2][y1-1] + s[x1-1][y1-1]
.
#include <bits/stdc++.h>
using namespace std;
int n, m, q;
const int N = 1010, M = 1010;
int s[N][M];
int main(){
cin >> n >> m >> q;
for(int i = 1; i <= n; i++)
for(int j = 1; j <= m; j++){
cin >> s[i][j];
s[i][j] = s[i][j] + s[i][j - 1] + s[i - 1][j] - s[i - 1][j - 1];
}
while(q --){
int x1, y1, x2, y2;
cin >> x1 >> y1 >> x2 >> y2;
cout << s[x2][y2] - s[x1 - 1][y2] - s[x2][y1 - 1] + s[x1 - 1][y1 - 1] << endl;
}
return 0;
}