AcWing_1015 摘花生(线性DP)

AcWing

1015. 摘花生

f[i][j]:所有到(i, j)的方案中,花生总数的最大值。

状态转移方程:f[i][j] = max(f[i - 1][j], f[i][j - 1]) + w[i][j].

#include <bits/stdc++.h>
using namespace std;
int t, r, c;
const int N = 110;
int w[N][N];
int f[N][N];
int main(){
    ios::sync_with_stdio(0);
    cin.tie(0); cout.tie(0);
    cin >> t;
    while(t--){
        cin >> r >> c;
        for(int i = 1; i <= r; i++) for(int j = 1; j <= c; j++) cin >> w[i][j];
        for(int i = 1; i <= r; i++) for(int j = 1; j <= c; j++)
            f[i][j] = max(f[i - 1][j], f[i][j - 1]) + w[i][j];
        cout << f[r][c] << endl;
    }
    return 0;
}